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Pani-rosa [81]
3 years ago
13

The K w for water at 0 ∘ C is 0.12 × 10 − 14 . Calculate the pH of a neutral aqueous solution at 0 ∘ C.

Chemistry
1 answer:
dusya [7]3 years ago
6 0

Answer:

pH = 7.46

Explanation:

2H₂O  ⇄  H₃O⁺  .  OH⁻          Kw = [H₃O⁺] . [OH⁻]

[H₃O⁺] = [OH⁻]

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸  M

- log  [H₃O⁺] = pH

- log 3.46×10⁻⁸ = pH → 7.46

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Answer:

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Explanation:

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L is the Avogadro's constant which is

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From the question we have

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We have the final answer as

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