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Elza [17]
3 years ago
5

There are two different compounds of sulfur and fluorine.

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
5 0
What's your question......................
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When the molecules of gases are heated, the average kinetic energy of the molecules increases,
serious [3.7K]
True is the answer to this
6 0
3 years ago
Indicate whether aqueous solutions of each of the following solutes will contain only ions, only molecules, or mostly molecules
Zanzabum

Answer:

Following are the solution to the given points:

Explanation:

In point a, the answer is only ions because of NH_4Cl has a strong electrolyte.

In point b, the answer is the only molecules because of ethanol CH_3CH_2OH, it has a nonelectrolyte.

In point c, the answer is the few ions because of hydrocyanic acid HCN, which has a weak electrolyte.

6 0
3 years ago
Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan
natka813 [3]

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

  • Ag2SO4 ↔ 2Ag+  +  SO42-

           S                2S            S...............in the equilibrium

  • Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

4 0
3 years ago
A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,
Scorpion4ik [409]

<u>Answer:</u> The value of K_c is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For Sb_2S_3</u>

Given mass of Sb_2S_3 = 1.00 kg = 1000 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of Sb_2S_3 = 339.7 g/mol

Putting values in equation 1, we get:

\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol

  • <u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

                  Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)

Initial:            2.944      5

At eqllm:      2.944-x     5-3x         2x        3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}

The expression of K_c for above equation, we get:

K_c=\frac{[H_2S]^3}{[H_2]^3}

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412

Hence, the value of K_c is coming out to be 0.412

3 0
3 years ago
A certain satellite orbiting Earth has a speed of about 17,000 miles/hour. What is its approximate speed expressed to the correc
algol [13]

Answer:- The speed of the satellite is 7.6\frac{kilometer}{second} .

Solution:- It's a unit conversion problem that could be solved using dimensional analysis which is also known as train trail method.

The given speed of the satellite is 17000 miles per hour and we are asked to convert it to kilometers per second.

given:

1 Kilometer = 0.62 mile

1 hour = 3600 second

Let's use this given info and plug in the values to make the set up as:

17000\frac{mile}{hour}(\frac{1 kilometer}{0.62 mile})(\frac{1 hour}{3600 second})

= 7.616\frac{kilometer}{second}

We round the answer to two significant figures, since the given number(17000) has only two significant figures.

Hence, the speed of the satellite is 7.6\frac{kilometer}{second} .

6 0
3 years ago
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