621.4L
Explanation:
Given parameters:
Initial volume = 547L
Initial temperature = 331K
Final temperature = 376K
Unknown:
Final volume = ?
Solution:
The appropriate gas law to use is the Charles's law.
The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.
The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".
Mathematically;
V₁ is the initial volume
T₁ is the initial temperature
V₂ is the final volume
T₂ is the final temperature
Since the unknown is the final volume, we make it the subject of the expression;
V₂ = 
V₂ = 621.4L
learn more:
Boyle's law brainly.com/question/8928288
#learnwithBrainly
Normal rainwater has a pH of 5.6<span> (slightly acidic)</span>
Answer: There are 
atoms of hydrogen are present in 40g of urea, 
.
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.
According to the mole concept, 1 mole of every substance contains 
atoms.
So, the number of atoms present in 0.67 moles are as follows.
In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.
Thus, we can conclude that there are atoms of hydrogen are present in 40g of urea, .
Answer:
a) 5.4 * 10^-4 moles
b) 8.2 moles
c) 0.26 moles
d) 20.76 moles
Explanation:
a)Since 1 mole of a substance has 6.02 * 10^23 atoms
x moles is present in 3.25 x 1020 atoms of lead
3.25 x 1020 atoms of lead/6.02 * 10^23 atoms = 5.4 * 10^-4 moles
b) Since 1 mole of a substance has 6.02 * 10^23 molecules
x moles is present in 4.96 x 1024 molecules of glucose
x = 4.96 x 1024 molecules of glucose/6.02 * 10^23 molecules = 8.2 moles
c) Since 1 mole of a substance has 6.02 * 10^23 formula units
x moles is present in 1.56 x 1023 formula units of sodium hydroxide
x = 1.56 x 1023 formula units /6.02 * 10^23 = 0.26 moles
d) Since 1 mole of a substance has 6.02 * 10^23 ions
x moles is present in 1.25 x 1025 copper(ll) ions
x = 1.25 x 1025 copper(ll) ions/6.02 * 10^23 ions = 20.76 moles
Answer:
Therefore F ∠ 2.5N
Explanation:
Definition of Work:
It is the amount of energy transferred.
Mathematical expression:
W = F × d
By taking the friction into count it will define as:
Input work = work against friction × output work
No we will put the values:
25 J = w + 10 m
j = kg m²/s²
25 kg m²/s² = w + 10 m
when friction is exist then w > 0
25 kg m²/s² - 10 m > 0
15 N > 0
Therefore F ∠ 2.5N
