Question

A flexible container at an initial volume of 6.13 L contains 8.51 mol of gas. More gas is then added to the container until it reaches a final volume of 18.5 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answer 1

Explanation:

According to Avogadro's law, equal volumes of all the gases at same temperature and pressure will also, have same number of molecules.

That is,             $V \propto n$

or                      $\frac{V}{n}$ = k

Since, it is given that $V_{1}$ is 6.13 L, $n_{1}$ is 8.51 mol, and $V_{2}$ is 18.5 L.

Hence, calculate the $n_{2}$ as follows.

                        $\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

                        $\frac{6.13 L}{8.51 mol} = \frac{18.5 L}{n_{2}}$  

                           ${n_{2}}$ = 0.35 mol

Thus, we can conclude that the number of moles of gas added to the container is 0.35 mol.