Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
iscovers that the density of acetone is . calculate the volume of acetone the student should pour out. round your answer to significant digits.
1 answer:
Answer:
70.15 cm³
Solution:
Data Given;
Mass = 55 g
Density = 0.784 g.cm⁻³
Required:
Volume = ?
Formula Used:
Density = Mass ÷ Volume
Solving for Volume,
Volume = Mass ÷ Density
Putting values,
Volume = 55 g ÷ 0.784 g.cm⁻³
Volume = 70.15 cm³
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In which region is the substance in both the solid phase and the liquid phase ?
2
Answer:
139.98 g to nearest hundredth.
Explanation:
Using Avogadro's Number:
One mole (167.26 g) of Erbium equates to 6.022141 * 10^23 atoms.
So 5.04 * 10^23 = 167.26 * 5.04/6.022141
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