Question

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Answer 1

• No of protons=No of electrons=15

Mass no:-No of neutrons+No of protons

$\\ \tt\longmapsto 15+16=31$

Now

• It has atomic no 15 hence its Phosphorus(P)

Electronic configuration:-

$\\ \tt\longmapsto 1s^22s^22p^63s^23p^3$.

• Valency=3

Chloride formula:-

$\\ \tt\longmapsto XCl_3$

or.

$\\ \tt\longmapsto PCl_3$

Answer 2

(a)(i) Mass number of X=32.065u

(ii) Electronic configuration of X=[Ne] 3s² 3p⁴

(b)(i) Formula of a chloride of X=Disulfur Dichloride=S2Cl2