Answer :
Total carbons are in the structure = 13
Primary carbons are in the structure = 5
Secondary carbons are in the structure = 6
Tertiary carbons are in the structure = 1
Quaternary carbons are in the structure = 1
Explanation :
Primary carbon : It is a carbon atom that is bound to only 1 carbon atom.
Secondary carbon : It is a carbon atom that is bound to 2 carbon atom.
Tertiary carbon : It is a carbon atom that is bound to 3 carbon atom.
Quaternary carbon : It is a carbon atom that is bound to 4 carbon atom.
As we are given the name of compound is, 2,2-dimethyl-4-propyloctane.
In this compound, eight carbon are align in a straight line, two methyl group are attached at 2nd position of the carbon in main chain and a propyl group that is three membered carbon chain is attached at 4th position of the carbon in main chain.
The given compound skeletal structure is shown below.
Answer:
Cells have many structures inside them called organelles. These organelles are like organs in a human that help a organism survive. Mitochondria are the power House of the cell and provide energy for the cell.
Explanation:
Unsustainable way of managing resources means using resources in an unjustifiable manner, using without keeping in the needs for future generations. That is disobeying the principles of sustainability.
For examples release of toxic industrial wastes in rivers and thus, polluting it. Or, Deforestation of land for agricultural or industrial purposes. Thus, reducing the oxygen carrying capacity of Earth.
Answer:
ΔH = ΔH₁ + ΔH₂ - ΔH₃
Explanation:
Given that:
1. A → 2B
2. B → C + D
3. E → 2D
Assuming from the corresponding ΔH for process 1, 2 and 3 are ΔH₁, ΔH₂, ΔH₃ respectively.
To estimate the ΔH for the process A → 2C + E
We multiply 2 with equation 2 where (B → C + D)
2B → 2C + 2D ⇒ 2ΔH₂
Also, let's switch equation (3), such that we have,
2D → E -ΔH₃
The summation of all the equation result into :
A → 2C + E
where; ΔH = ΔH₁ + ΔH₂ - ΔH₃
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<h2><em><u>Technically yes but no because you have to fill the 3s orbital before the 5s orbital</u></em></h2>
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