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Schach [20]
3 years ago
14

Explain the similarities and differences between a 1M solution of NaOH and a 1m solution of NaOH

Chemistry
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

Similarity - 1 mol of NaOH in 1M and 1m.

Difference - 1M - 1 mol NaOH in 1L solution,

1m - 1 mol NaOH in 1000g solvent (water).

Explanation:

M - Molarity,  the number moles of solute are dissolved in 1 L of solution.

m - Molality is the number of moles of solute per 1 (kg) kilogram = 1000 g of solvent.

Similarity - 1 mol of NaOH in 1M and 1m.

Difference - 1M - 1 mol NaOH in 1L solution,

1m - 1 mol NaOH in 1000g solvent (water).

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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
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Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







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3 years ago
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Suppose you decide to define your own temperature scale using the freezing point (13 degrees C) and boiling point (360 degrees C
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M.P of  oleic acid = 13 deg C 
<span>B.Pof  oleic acid = 360 deg C </span>



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<span>So 1 deg O = 3.47 deg C </span>

<span>The scale do not start at 0 deg C, it starts at 13 deg C. So to convert deg C to deg O,
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<span>convert  O to C multiply by 3.47 then add 13 </span>

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