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astra-53 [7]
3 years ago
12

The five-number summary for a data set is given below. 1.3 3.8 4.1 4.4 12.4 Using the 1.5 x IQR Rule, any data value _____ than

2.9 should be flagged as a suspected outlier. Please type the correct answer in the following input field, and then select the submit answer button or press the enter key when finished.
Mathematics
1 answer:
mixas84 [53]3 years ago
3 0

Answer:

Any data value <u>less</u> than 2.9 should be flagged as a suspected outlier.

Step-by-step explanation:

We have been given the five-number summary for a data set is given below. 1.3  3.8  4.1  4.4  12.4. Using the 1.5 x IQR Rule, any data value _____ than 2.9 should be flagged as a suspected outlier. We are asked to fill in the given blank.

Our given points (1.3  3.8  4.1  4.4  12.4) represent minimum point, 1st quartile, median, 3rd quartile and maximum point.

First of all, we will find interquartile range by subtracting 1st quartile from 3rd quartile.

IQR=4.4-3.8=0.6

Using 1.5 x IQR Rule, we will get our outliers as:

3.8-(1.5\times IQR)\Rightarrow3.8-(1.5\times 0.6)=3.8-(0.9)=2.9    

12.4+(1.5\times IQR)\Rightarrow12.4+(1.5\times 0.6)=12.4+(0.9)=13.3

Therefore, any data value less than 2.9 and greater than 13.3 should be flagged as a suspected outlier.

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beks73 [17]
<span>x= -8 + y
-9x + 6y= 9

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-9x + 6y= 9
-9(-8 + y) + 6y= 9
72 - 9y + 6y = 9
-3y = -63
    y = 21

<span>x= -8 + y
</span><span>x= -8 + 21
x = 13

solution (13, 21)</span>
7 0
3 years ago
Evaluate. -6-6x(-5)<br><br> Please help, would really appreciate it
sweet-ann [11.9K]
Order of operations so -6 × -5 = 30

-6 + 30 = 24 is the answer

Hope this helps!
8 0
3 years ago
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Water flows through pipe at a rate of 490 Milliliters every 6.5 hours express this rate of flow influence one's permanent round
likoan [24]

Answer:

To the nearest hundredth, the rate of flow will be 75.38 mm/hr

Step-by-step explanation:

Here in this case, we are to express the rate at which the water flow and round it up to the nearest hundredth.

We are told that water flows through the pipe at a rate of 490 mm every 6.5 hours.

Now, the rate will be 490/6.5 = 75.384615384615 mm/hr

Rounding this value to the nearest hundredth, we have 75.38 mm/hr

7 0
3 years ago
Paul has 2/3 as many postcards as Shawn. The number of postcards Shawn has is 4/5 of the number of postcards Tim has. If the thr
ahrayia [7]

Tim has 56 more postcards than Paul.

Step-by-step explanation:

Total postcards boys have = 280

Let,

x = Paul's postcards

y = Shawn's postcards

z = Tim's postcards

According to given statement;

x + y + z = 280      Eqn 1

x=\frac{2}{3}y                   Eqn 2

y = \frac{4}{5}z                   Eqn 3

Putting value of y from Eqn 3 in Eqn 2

x=\frac{2}{3}*\frac{4}{5}z\\\\x=\frac{8}{15}z            Eqn 4

Putting value of x and y from Eqn 4 and Eqn 3 in Eqn 1

\frac{8}{15}z+\frac{4}{5}z+z=280\\\\\frac{8z+12z+15z}{15}=280\\\\\frac{35z}{15}=280\\\\

Multiplying both sides by \frac{15}{35}

\frac{15}{35}*\frac{35}{15}z=280*\frac{15}{35}\\z=120

Putting z=120 in Eqn 3

y=\frac{4}{5}*120\\y=96

Putting y=96 in Eqn 2

x=\frac{2}{3}*96\\x=64

Difference of Tim and Paul = 120-64 = 56

Tim has 56 more postcards than Paul.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/10557938
  • brainly.com/question/10600222

#LearnwithBrainly

7 0
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The number of text messages Lelah sent each month is shown in the table. She can send no more than 55 messages each month withou
Svetlanka [38]
$0.75, because she only went over once in January, and twice in February. March was 55 and April was 51. So .25+.50=.75
3 0
4 years ago
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