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Lubov Fominskaja [6]
2 years ago
6

A credit card has an annual percentage rate of 23 988% the balanced owed is $1450.00. Assuming no additional charges are made. W

hat is the minimum monthly payment in dollars, required to pay off the balance in 12 months? (No links)
120.83
149.82
175.33
299.65

Mathematics
1 answer:
tatyana61 [14]2 years ago
8 0
The answer should be 120.83
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Two cars are traveling in opposite directions at different rates. Two hours later, the cars are 110 mi apart. Express the distan
Andre45 [30]

Answer:

110 - x

Step-by-step explanation:

8 0
2 years ago
Jamie has a bag containing purple, pink, yellow, and blue marbles. There are a total of 40 marbles in the bag. Jamie randomly se
Ad libitum [116K]

Answer:

1 pink marble

Step-by-step explanation:

If Jamie selected 10 times the pink marble in a total of 420 tries, we can assume that the proportion of pink marble in the total number of marbles is:

10 / 420 = 1/42

So to predict a good number of pink marbles in the total 40 marbles, we just need to multiply the 40 marbles by the proportion found above:

pink marble = 40 * (1/42) = 0.9524

As this number needs to be a whole number, a good assumption is that there is 1 pink marble in the 40 marbles.

8 0
3 years ago
Solve the following quadratic equation. Express your answers in exact form.
wlad13 [49]

Answer:

x = (2+√10)/ 3 and x= (2-√10/3)

Step-by-step explanation:

g(x) = -3x² +4x +2

use the quadratic formula x= (-b±√b²-4ac)/2a, when g(x) = ax² +bx +c

x= [-4 ±√4²-4*(-3)*2] / 2*(-3) , solve under the square root

x= (-4 ± √16 +24) / -6 , add under the radical

x= (-4 ±√40) / -6, simplify the square root

x= (-4 ±2√10) /-6, factor -2

x= -2 (2±√10)/-2 *3, simplify -2

x= (2±√10)/3

Therefore,

x = (2+√10)/ 3 and x= (2-√10/3)

5 0
3 years ago
The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC
DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x²  ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)²  ⇒(2)

Equating (1) and (2)

∴  10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴  10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in  and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0
2 years ago
17. Each person on a Ferris wheel pays $6.50
patriot [66]

Answer:

$468

Step-by-step explanation:

6.5x72 passengers= $468

6 0
3 years ago
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