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Katyanochek1 [597]
4 years ago
15

PLEASE SHOW WORK!!!!!!

Mathematics
1 answer:
Helen [10]4 years ago
8 0

Answer:

Sure thing!

For the first equation 6v+38≤ -4

The answer would be v≤-7

and for the second equation 2(v+3)≥-2

the answer would be v≥-4

Step-by-step explanation:

6v+38≤ -4

Subtract 38 from both sides

6v+38-38≤-4-38

Simplify

6v≤-42

Divide both sides by 6

6v/6≤-42/6

Simplify

v≤-7

SAME THING FOR THE OTHER

2(v+3)≥-2

Divide both sides by 2

2(v+3)/2≥-2/2

Simplify

v+3≥-1

Subtract 3 from both sides

v+3-3≥-1-3

And finally, simplify

v≥-4

PLEASE MARK AS BRAINLIEST

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Answer:

The coordinate of the  vertex of the parabola is (h,k) =  (3,20)

Step-by-step explanation:

The given equation of the parabola is y=-5x^2+30x-25

Now, the General Parabolic Equation is of the form:

y = a (x-h)^2 + k, then the vertex is the point (h, k).

Now, to covert the given equation in the standard form:

y=-5x^2+30x-25   = -5(x^2  -6x   + 5)

Using the COMPLETE THE SQUARE METHOD,

-5(x^2  -6x   + 5)  = -5(x^2  -6x  +  (3)^2 +  5  - (3)^2)\\\implies -5(((x^2  -6x +(3)^2)  + 5 - 9)\\= -5((x-3)^3 -4)\\= -5(x-3)^2 + 20

ory = -5(x-3)^2 + 20

⇒The general formed equation of the given parabola is

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Comparing this with general form, we get

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Hence, the coordinate of the  vertex of the parabola is (h,k) =  (3,20)

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