Barnard's star is a near neighbor of the Sun whose properties we know quite well. It is a type M4V with absolute magnitude 13.22
1 answer:
Answer:
The star is at a distance of 100 parsecs.
Explanation:
The distance can be determined by means of the distance modulus:
(1)
Where M is the absolute magnitude, m is the apparent magnitude and d is the distance in units of parsec.
Therefore, d can be isolated from equation 1
Then, Applying logarithmic properties it is gotten:
(2)
The absolute magnitude is the intrinsic brightness of a star, while the apparent magnitude is the apparent brightness that a star will appear to have as is seen from the Earth.
Since both have the same spectral type is absolute magnitude will be the same.
Finally, equation 2 can be used:
Hence, the star is at a distance of 100 parsecs.
Key term:
Parsec: Parallax of arc seconds
You might be interested in
Answer:
I = 0.483 kgm^2
Explanation:
To know what is the moment of inertia I of the boxer's forearm you use the following formula:
(1)
τ: torque exerted by the forearm
I: moment of inertia
α: angular acceleration = 125 rad/s^2
You calculate the torque by using the information about the force (1.95*10^3 N) and the lever arm (3.1 cm = 0.031m)
Next, you replace this value of τ in the equation (1) and solve for I:
hence, the moment of inertia of the forearm is 0.483 kgm^2
<h3><u>Answer</u></h3>
- Distance is equal to the Total Distance covered by a body, from the initial till the final point
- Displacement is equal to the shortest distance between two points.
- So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.
- This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path
☯ Distance is a scalar quantity and has only magnitude but no direction.
☯ Displacement is a vector quantity and has both magnitude and direction.
☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.