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3 years ago

How do i get a negative cube when i calculate density

Physics

2 answers:

fgiga [73]3 years ago

8 0

374848282!,!( rnanxjcifjejzxj

NNADVOKAT [17]3 years ago

8 0

Answer:

density should always be positive, you must have missed a sign somewhere

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Starting from a location with position vector 1,=−17.5 m and 1,=23.1 m , a rabbit hops around for 10.7 seconds with average velo

Andru [333]

By definition of average velocity,

$\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t} = \dfrac{(x_2-x_1)\,\vec\imath + (y_2-y_1)\,\vec\jmath}{10.7\,\mathrm s}$

$\vec v_{\rm ave} = (-2.25\,\vec\imath + 1.79\,\vec\jmath)\dfrac{\rm m}{\rm s}$

and $x_1=-17.5\,\mathrm m$ and $y_1=23.1\,\mathrm m$ , then

$-2.25\dfrac{\rm m}{\rm s} = \dfrac{x_2 - (-17.5\,\mathrm m)}{10.7\,\mathrm s} \\\\ 1.79\dfrac{\rm m}{\rm s} = \dfrac{y_2 - 23.1\,\mathrm m}{10.7\,\mathrm s}$

Solve for $x_2$ and $y_2$ :

$x_2 = 17.5\,\mathrm m + \left(-2.25\dfrac{\rm m}{\rm s}\right)(10.7\,\mathrm s) \approx \boxed{-6.58\,\mathrm m}$

$y_2 = 23.1\,\mathrm m + \left(1.79\dfrac{\rm m}{\rm s}\right)(10.7\,\mathrm s) \approx \boxed{42.3\,\mathrm m}$

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2 years ago

To model this process, assume two charged spherical conductors are connected by a long conducting wire and a 1.20-mC charge is p

il63 [147K]

Answer:

Part a: The electric potential of each sphere is 1.35x10⁸V

Part b: The electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

Explanation:

As the complete question is not given, the similar question is attached herewith. The values are used as indicated in the given question

Let r_1 = 6 cm=0.06 m

r2 = 2 cm = 0.02 m

Q = 1.2 mC

Let q1 and q2 are the charges on each sphere.

q1 + q2 = 1.2 mC -------(1)

In the equilibrium, V1 = V2

k*q1/r1 = k*q2/r2

q1/0.06 = q2/0.02

q1/q2 = 0.06/0.02

q1/q2 = 3 ---------(2)

On solving equation 1 and 2

we get

q1 = 0.9 mC

q2 = 0.3 mC

V1 = k*q1/r1 = (9*10^9*0.9*10^-3)/0.06 = 1.35*10^8 Volts

V2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02 = 1.35*10^8 Volts

So the electric potential of each sphere is 1.35x10⁸V

Part b

Now the electric potential is given as

E1 = k*q1/r1^2 = 9*10^9*0.9*10^-3/0.06^2 = 2.25*10^9 N/C

E2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02^2 = 6.75*10^9 N/C

So the electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

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3 years ago

Examples of the period, frequency, speed of a wave in a sentence?

Kamila [148]

Hi There! :)

Examples of the period, frequency, speed of a wave in a sentence?

Examples

•He indicated the space behind him with a wave of a hand.

•On land only the grass and trees wave, but the water itself is rippled by the wind.

•But wherever it may turn there always will be the wave anticipating its movement.

•Harbor was completely submerged by the great wave, which still came

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3 years ago

What is a Lever?

NemiM [27]

Lever: a bar used to move something
Wedge: a tool used to go in between object to put them in place
Incline plane : a ramp it’s used to help rise heavy things
Pulley: it’s a wheel that supports movement and change of direction

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3 years ago

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Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k

Dennis_Churaev [7]

Almost all telescopes have a circular mirror. The area of a circle is proportional to $r^2$ where $r$ is the radius of the circle, the constant of proportionality being $4\pi$
$S =4\pi r^2$
Therefore the area of 150 meter telescope would be
$S_1/S_2=(r_1/r_2)^2 =(75/5)^2 =15^2=225$
times bigger than the area of the smaller (10 meter) telescope.

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3 years ago

How do i get a negative cube when i calculate density​

How do i get a negative cube when i calculate density