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Degger [83]
3 years ago
9

Which type of energy releases greenhouse gases when used to make electricity?

Physics
2 answers:
timurjin [86]3 years ago
5 0

Answer is: biomass.

Most often greenhouse gases are carbon dioxide and methane. They come from burning multiple substances: coal, petroleum, natural gas.

Carbon dioxide (CO₂) and energy (heat) is produced by combustion of fossil fuels, that energy is used for producing electricity (the heat energy of combustion is converted into mechanical energy).

For example, coal power plants use coal to heat water into steam, that steam than move a steam turbine, which generate electricity.

Elan Coil [88]3 years ago
4 0
A) Geothermal
B) Hydroelectric
C)Biomass
D) Wind

I assume this is the four options you had, correct?

i think that biomass is the only one that would release the greenhouse gases. I once heard, it may not be true, that biomass has more co2 released than coal.
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A baseball with a mass of 0.80 kg is given an acceleration of 20.00 m/s. How much net force was applied to the ball
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a x m = f

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A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
torisob [31]

Answer:

0.1 s

Explanation:

The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log

So F - f = ma

F - μmg = ma

F/m - μg = a

So, substituting the values of the variables into the equation, we have

a = F/m - μg

a = 2850 N/300 kg - 0.45 × 9.8 m/s²

a = 9.5 m/s² - 4.41 m/s²

a = 5.09 m/s²

Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.

So, making t subject of the formula, we have

t = (v - u)/a

substituting the values of the variables into the equation, we have

t = (v - u)/a

t = (0.5 m/s - 0 m/s)/5.09 m/s²

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t = 0.098 s

t ≅ 0.1 s

6 0
2 years ago
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