19. A material with a shape that remains unchanged when it is moved from one container to another is a(n)________

1 answer:

8 0

A material with a shape that remains unchanged when it is moved from one container to another is a solid.
Liquids don't have a shape - they can assume the shape of any container they are put into. Whereas solids don't change the shape they already have even though they are placed in various other containers.

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Cylinder with a mass of 12g has a radius measuring 2cm and height of 6cm what is its density

lakkis [162]

Answer:

Given:

m = 12 g, the mass of the cylinder

r = 2 cm, the radius of the cylinder

h = 6 cm, the height of the cylinder.

Calculate the volume, V, of the cylinder.

V = πr²h

= π*(2 cm)²*(6 cm)

= 75.398 cm³

By definition,

density = mass/volume.

Therefore,

density = m/V

= (12 g)/(75.398 cm³)

= 0.159 g/cm³

= 0.16 g/cm³ (nearest hundredth)

Answer: 0.16 g/cm³

8 0

3 years ago

A plane has a cruising speed of 100 miles per hour when there is no wind. At this speed, the plane flew 600 miles with the wind

alina1380 [7]

The solution for this problem is:
Let x = speed of wind

Speed of plane with the wind = x + 100

Speed of plane against the wind = 100 -x

We will be using the formula for distance which is (Rate)(Time), getting the formula for time would be distance/rate Time to travel 600 miles with the wind = Time to travel 400 miles against the wind 600/(x + 100) = 400/(100 - x)

400(x + 100) = 600(100 - x)

400x + 40000 = 60000 - 600x

1000x = 20000

x = 20000/1000

x = 20 mph

8 0

3 years ago

Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st

Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have reaction called halohydrin formation. This is a markovnikov reaction with anti configuration. Therefore the halogen in this case "Br" and the "OH" must have different configurations. Additionally, in this molecule both carbons have the same substitution, so the "OH" can go in any carbon.

Finally, in the product we will have chiral carbons, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!