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Crank
3 years ago
10

II. Enumerate the following.

Chemistry
1 answer:
Andrej [43]3 years ago
4 0

Answer:

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now go ogle me et

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Questions 18-20 refer to the reaction 2NH3 (g) ↔ N2 (g) + 3H2 (g), and ΔH = 92.2 kJ.
Fittoniya [83]
18. <span>Answer is </span>A

<span>  
<span>Since the enthalpy of reaction is positive, the forward reaction is<span> an endothermic reaction which means the energy is gained from the surrounding to happen the reaction. If the temperature decreases, according to the </span></span>Le Chatelier's principle, the system tries to become equilibrium by increasing temperature. Since forward reaction is endothermic (because of the bond breaking), the backward reaction is exothermic (because of the bond making) which releases the energy to the surroundings. This makes the increase of temperature. So if the backward reaction is promoted because of the decrease of temperature, then the concentration of H</span><span>₂ will decrease.</span>

<span>
</span>

19. Answer is A.

The reactant side has 2 moles/molecules of reactants and the product side has 4 moles/molecules of products which come from 1 N₂(g) and 3 H₂<span>(g). If the pressure is reduced in the system, according to the Le Chatelier's principle, the system tries to increase the pressure. </span><span>Hence, forward reaction is promoted because of the higher number of molecules in product side. If the forward reaction is promoted, the concentration of NH</span>₃(g) will decreased.


<span>20. </span>Answer is C.

If the concentration of reactant is increased in the system, according to the Le Chatelier's principle, the system tries to reduce the concentration of that reactant. So if NH₃(g) concentration is increased, then to be equilibrium, the forward reaction will be promoted. Then the concentration of N₂<span>(g) will increase.</span>

<span> </span>

4 0
3 years ago
Josie created a Venn Diagram to determine the differences and similarities between weather and climate. PLSSS HELP I HAVE 15 MIN
DENIUS [597]

Answer:

Climate is long time intervals and weather is short time intervals

Explanation:

4 0
3 years ago
Calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​
Fynjy0 [20]

Moles of benzene

  • 70/90=7/9=0.8mol

moles of CCl_4

  • 30/154
  • 0.2mol

Now

\\ \rm\Rrightarrow \chi_{C_6H_6}

\\ \rm\Rrightarrow \dfrac{\chi_{C_6H_6}}{\chi_{sol^n}}

\\ \rm\Rrightarrow \dfrac{0.8}{0.8+0.2}

\\ \rm\Rrightarrow \dfrac{0.8}{1}

\\ \rm\Rrightarrow 0.8

4 0
2 years ago
water interacts with polar substances like –oh groups but not with non-polar substances like methyl (−ch3) or ethyl groups (−ch2
Brilliant_brown [7]

CH3OH and CH3CH2CH2OH will easily dissolve in water based on polarity not on size.

<h3>What is Polarity ?</h3>

In chemistry, polarity describes the type of bonds that exist between atoms. Atoms share electrons when they join forces to form chemical bonds. When one of the atoms applies a stronger attractive force to the bond's electrons, a polar molecule is created.

  • For instance, the chlorine atom is slightly negatively charged while the hydrogen atom in hydrogen chloride is slightly positively charged.

  • Water is polar due to its form even though its molecules have no net charge. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are drawn to other polar molecules and to one another as a result.

Learn more about Polarity here:

brainly.com/question/26849258

#SPJ4

7 0
1 year ago
An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.
____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

(c) Force needed to open the door =  15106 N

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

\rho_{air}=\frac{P}{R*T}

First, we change the units of P to Pa and T to deg K:

P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K

Then we have

\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N

7 0
3 years ago
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