Answer:
(11, 11)
Step-by-step explanation:
Solve by substitution:
1. set the equations equal to each other

2. simplify

3. substitute the value of x into an equation

Length of the side = 9 cm
Diagonal =
cm
Solution:
Area of the square = 81 square centimeters
In square all sides are equal.
Area of the square = side × side
Side × side = 81
Side² = 9² (∵81 = 9²)
Taking square root on both sides, we get
Side = 9 cm
Length of the side = 9 cm
To find the length of the diagonal:
In square all the angles are right angle.
Diagonal splits the square into two right angle triangle.
Using Pythagoras theorem,
<em>In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.</em>
Here, diagonal is the hypotenuse.



Taking square root on both side,
Diagonal =
cm
Answer:
Step-by-step explanation:
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is


Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)


Assuming you meant is

The answer would be :




Hope this helps !
Photon
However, your equation seems weird :o