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3 years ago

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A hyperbola centered at the origin has a vertex at (3, 0) and a focus of the hyperbola is located at (9, 0). What are the equati

ons of the directrices?
x = Â±

2 answers:

Alborosie3 years ago

8 0

The answer is 1.,.....

frez [133]3 years ago

7 0

It's 1 i agree with the other person because i just took the assignment and got it correct.

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The area, a, of a square whose side length is n

svetlana [45]

Answer:

a*n=area

Step-by-step explanation:

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3 years ago

What is the volume of the composite figure. I said 36 but it is wrong.

scZoUnD [109]

Answer:

108

Step-by-step explanation:

You are correct for stating one tissue box has a volume for 36.

But notice there are 3 tissue boxes, so in order to find the total volume, you should add them up.

36+36+36=108

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3 years ago

Read 2 more answers

If line 1 has a slope of -4 and line 2 has a slope of 1/4, they are parallel<br> True<br> O False

Papessa [141]

Parallel lines need to have same slope
The lines have different slopes

It is false.

6 0

3 years ago

Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that

damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

For triangle ABC, we have:

$AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4$

$BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5$

$CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2$

For triangle DEF, we have:

$DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2$

$EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5$

$FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1$

Divide corresponding sides of the triangles to calculate the scale factor k

$k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}$

This gives

$k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}$

Evaluate the quotients

$k = 2 = 2 = 2$

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

3 0

2 years ago

Which ordered pair in the form (x, y) is a solution of this equation?

laiz [17]

Answer:

Substitute the x and y values from the ordered pairs into the equation, one by one, until both sides of the equation are equal.

Step-by-step explanation:

A. (-2,-3)

3 * (-2) - 4 * (-3) = 21

-6 + 12 = 21

6 = 21 <u>not equal</u>

B. (0,7)

3 * 0 - 4 * 7 = 21

0 - 28 = 21

- 28 = 21 <u>n</u><u>o</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u>

C. (7,0)

3 * 7 - 4 * 0 = 21

21 - 0 = 21

21 = 21 <u>equal</u>

6 0

2 years ago