Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3
Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.
selection B is appropriate.
Answer:
things and quality
Step-by-step explanation:
things and quality
x(t) = 20t
y(t) = 40t - 5t^2
Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y
x(5) = 20(5) becomes x(5) = 100
y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y(5) = 75
The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75
Answer: 0.75
Answer:
2.5, 5, 7.5
Step-by-step explanation:
Count.