Answer:
Here's what I get
Explanation:
1. Sugar
(a) Dissolving in water
The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.
2. Magnesium sulfate
(a) Dissolving in water
The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.
Answer:
Dihydrogen monoxide is one of the scientific names of water having the formula H2O, where H2 "dihydrogen" is a double hydrogen (Latin Hydrogenium — hydrogen), and O is "monoxide" (oxygen).
Answer:
fluoride ion with a charge of -1
Explanation:
If a fluorine atom gains an electron, it becomes a fluoride ion with an electric charge of -1.
Answer:
Reaction A and B are unfavorable.
Explanation:
Gibbs free energy is an energy which that can be use to convert into useful work.
ΔG°=ΔH°-TΔS°
ΔG°= Gibbs free energy
ΔH° = enthalpy of reaction
T = temperature of eh reaction
ΔS° = Entropy change
- If the Gibbs free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
- If the Gibbs free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .
According to given information in the question:
Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.
Answer:
<em>the </em><em>two </em><em>elements</em><em> </em><em>are </em><em>in </em><em>the</em><em> same</em><em> </em><em>period</em><em>,</em><em> with</em><em> </em><em>element </em><em>R </em><em>the </em><em>first</em><em> </em><em>element</em><em> </em><em>in </em><em>the</em><em> </em><em>period</em><em> </em><em>and </em><em>element </em><em>Q </em><em>the </em><em>last</em><em> </em><em>element</em>
