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WINSTONCH [101]
3 years ago
5

Of the following: H2(g); He(g); CO2(g); which would behave least like an ideal gas? Why?

Chemistry
1 answer:
Margarita [4]3 years ago
4 0
Answer:

CO2(g)

Because CO2 is the larges molecule with specific geometric, therefore it is not likely to behave as an ideal gas.
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Which statement best describes the movement of atoms in a solid? They are able to slide past each other. They spread apart as fa
ANTONII [103]
The answer is: They have no freedom to move.
However is not completely true, as even in a solid atoms still a move a bit (vibrations).

If atoms were able to slide past each other, then we would have a liquid not a solid. Liquids "flow" but never really "break apart" this is because atoms are sliding between them, think of these as a bucket of marbles rolling down a slope.

If they are free to move in all directions, then you have a gas; that's why someone uses perfume in a room, eventually everyone smells it.
4 0
3 years ago
Read 2 more answers
How many ATOMS of sulfur are present in 2.30 moles of sulfur trioxide?
zysi [14]

Answer:

1.39 Atoms

Explanation:

When converting from moles to atoms, multiply the number of moles by Avogadro's number

Multiply 2.30 moles by Avogadro's number (6.022*10^23)

= 1.3851 Atoms

=1.39 Atoms (sigfig)

8 0
3 years ago
What is the measure of AC?<br>5 units<br>13 units<br>26 units<br>39 units<br>​
Natalka [10]

Answer:

26 units

Explanation:

6 0
2 years ago
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Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a
s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

Explanation:

Partial pressure of the O_2gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

p_{o_2}=K_H\times\chi_{O_2}

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

0.0013=34860 bar\times \chi_{O_2}

\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}

Let the number of moles of O_2 gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L n_w=\frac{1000 g}{18 g/mol}=55.55 mol

\chi_{O_2}=\frac{n}{n+n_w}

2.56\times 10^{-5}=\frac{n}{n+55.55}

n=1.43\times 10^{-7} moles

Molarity=\frac{\text{Moles of}O_2}{Volume}

Molar concentration of oxygen gas in 1 L of water:

=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L

The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

4 0
3 years ago
What is the mass of alliminum?
Gennadij [26K]

Answer:

26.981539 u

Atomic number: 13

Symbol: Al

Electron configuration: [Ne] 3s²3p¹

5 0
3 years ago
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