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podryga [215]
3 years ago
13

URGENT

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

the answer is a

Step-by-step explanation:

all steps are shown

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4*2.36
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3 years ago
Given n = 875 and pˆ = 0.45, find the margin of error E that corresponds to a 95% confidence level.
sveticcg [70]

Answer:

The margin of error E that corresponds to a 95% confidence level is: E=0.03297

Step-by-step explanation:

The propocion is p = 0.45

The sample size n = 875

95% confidence level

Level of significance = 1-level of confidence

Level of significance = 1-0.95 = 0.05

The formula for the error is:

E = Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}

The value for Z_{0.05/2} =Z_{0.0250}= 1.96 according to the normal table

So:

E = 1.96\sqrt{\frac{0.45(1-0.45)}{875}}\\\\SE=0.03297

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Step-by-step explanation:

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