The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
brainly.com/question/76387
#SPJ1
Answer:
The answer is around 27.63 seconds.
Step-by-step explanation:
1 km equals 1000 meters so we have to multiply 10,500 and 1,000 which would equal 10,500,000 km. 10,500,000 divided by 380,000 which is around 27.63 seconds.
Answer:
4.88
Step-by-step explanation:
sinA=opposite/adjacent
sin24=x/12
12(0.40673664307)=x
x=4.88083971691
Answer:
1/3
Step-by-step explanation:
There are 6 sides on a dice. These are two of the possibilities. 2/6 is the same as 1/3.
Answer:
your a very beautiful dumb.asss
Step-by-step explanation:
go give your self a bj
