Answer:
2.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
3
,
5
)
Equation Form:
x
=
3
,
y
=
5
3.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
8
)
4.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
−
3
)
Step-by-step explanation:
Answer:0.8413
Step-by-step explanation:
Mean= 188, Std Dev. =20.8, Z=(x-mean)/Std Dev
P(X less than 167.2)= P(Z less than (167.2-188)/20.8)
=P(Z less than (-20.8/20.8))
=P(z less than -1)= P(Z less 1)
The value of 1 in the normal distribution table is 0.3413
So we add 0.5 to 0.3413 =0.8413
I think the answer is 1.125 or 1.13
** hope this helps**
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
