(AB) & (CD)
Most machines are fueled by gasoline and electricity
The second one since convection is the process by which heat is transferred from a solid surface to a non solid
A ) The first ball:
h = v o * t - g t² / 2
19.6 = 14.7 t + 9.8 t²/2
4.9 t² + 14.7 t - 19.6 = 0
t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8 = 9.8/9.8 = 1 s
The second ball:
v = v o - g t
0 = 14.7 - 9.8 t
9.8 t = 14.7
t = 1.5 ( upward )
h = 19.6 + 14.7 - 9.8 * 1.5 = 30.625 m
30.625 = 9.8 * t²/2
t² = 6.25
t = 2.5 s ( downward )
1.5 s + 2.5 s = 4 s
The difference: 4 s - 1 s = 3 s.
B ) The first ball:
v = v o + g t = 14.7 + 9.8 * 1 = 24.5 m/s
The second ball:
v = g * t = 9.8 * 3 = 24.5 m/s
C ) d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2 = 11.76 + 3.136 = 14.896 m
d 2 = 14.7 * 0.8 - 9.8* 0.8²/2 = 11.76 - 3.136 = 8.624 m
d 1 + d 2 = 14.896 + 8.624 = 23.52 m
To solve this problem we will apply the concepts of Boiling Point elevation and Freezing Point Depression. The mathematical expression that allows us to find the temperature range in which these phenomena occur is given by
Boiling Point Elevation
![\Delta T_b = K_b m](https://tex.z-dn.net/?f=%5CDelta%20T_b%20%3D%20K_b%20m)
Here,
= Constant ( Different for each solvent)
m = Molality
Freezing Point Depression
![\Delta T_f = K_f m](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20K_f%20m)
Here,
Constant ( Different for each solvent)
m = Molality
According to the statement we have that
![\Delta T_f = T_0 -T_f = 0-(-2.05)](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%20T_0%20-T_f%20%3D%200-%28-2.05%29)
![\Delta T_f = 2.05\°C](https://tex.z-dn.net/?f=%5CDelta%20T_f%20%3D%202.05%5C%C2%B0C)
From the two previous relation we can find the ratio between them, therefore
![\frac{\Delta T_b}{\Delta T_f} = \frac{K_b}{K_f}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20T_b%7D%7B%5CDelta%20T_f%7D%20%3D%20%5Cfrac%7BK_b%7D%7BK_f%7D)
![\frac{\Delta T_b}{\Delta T_f} = \frac{0.512}{1.86}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20T_b%7D%7B%5CDelta%20T_f%7D%20%3D%20%5Cfrac%7B0.512%7D%7B1.86%7D)
![\frac{\Delta T_b}{\Delta T_f} = 0.275](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20T_b%7D%7B%5CDelta%20T_f%7D%20%3D%200.275)
We already know the change in the freezing point, then
![\Delta T_b = 0.275 (\Delta T_f)](https://tex.z-dn.net/?f=%5CDelta%20T_b%20%3D%200.275%20%28%5CDelta%20T_f%29)
![\Delta T_b = 0.275 (2.05)](https://tex.z-dn.net/?f=%5CDelta%20T_b%20%3D%200.275%20%282.05%29)
![\Delta T_b = 0.5643\°C](https://tex.z-dn.net/?f=%5CDelta%20T_b%20%3D%200.5643%5C%C2%B0C)
The temperature difference in the boiling point is 100°C (Aqueous solution), therefore
![T_b -100 = 0.5643](https://tex.z-dn.net/?f=T_b%20-100%20%3D%200.5643)
![T_b = 100.56\°C](https://tex.z-dn.net/?f=T_b%20%3D%20100.56%5C%C2%B0C)
Therefore the boiling point of an aqueous solution is ![100.56\°C](https://tex.z-dn.net/?f=100.56%5C%C2%B0C)
Answer:
Height of ramp = 17.49 m
Explanation:
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering horizontal motion of skier
Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.
![63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds](https://tex.z-dn.net/?f=63%3D%2033t%2B%5Cfrac%7B1%7D%7B2%7D%20%2A0%2At%5E2%5C%5C%20%5C%5C%20t%3D1.909seconds)
The vertical distance traveled in 1.909 seconds is the height of ramp
Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8
, time = 1.909 s and we need to find displacement.
![s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m](https://tex.z-dn.net/?f=s%3D%200%2A1.909%2B%5Cfrac%7B1%7D%7B2%7D%20%2A9.8%2A1.909%5E2%5C%5C%20%5C%5C%20s%3D17.49%20m)
So height of ramp = 17.49 m