Answer:
Correct answer: Ek = 2,028.6 J
Explanation:
Ek = m v²/2 = 0.023 · 220² = 0.023 · 176,400/2 = 2,028.6 J
God is with you!!!
Answer:
V(t1-t0)
Explanation:
Moving 'uniformly' means constant velocity (speed). the formula for constant speed motion is
=( change in position/ change in time)
where,
V is speed
given in the statement :
change in time = t = t1-t0
let the constant speed be ' V '
disance = X = X1-X0
applying the above mentioned formula: V = ![\frac{X}{t}](https://tex.z-dn.net/?f=%5Cfrac%7BX%7D%7Bt%7D)
V = X/t
X = Vt
the distance X1-X0 = Vt =V(t1-t0)
Answer:
a) 0.658 seconds
b) 0.96 inches
Explanation:
![v=u+at\\\Rightarrow 0=4.5-32.1\times t\\\Rightarrow \frac{-4.5}{-32.1}=t\\\Rightarrow t=0.14 \s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%200%3D4.5-32.1%5Ctimes%20t%5C%5C%5CRightarrow%20%5Cfrac%7B-4.5%7D%7B-32.1%7D%3Dt%5C%5C%5CRightarrow%20t%3D0.14%20%5Cs)
Time taken by the ball to reach the highest point is 0.14 seconds
![s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.5\times 0.14+\frac{1}{2}\times -32.1\times 0.14^2\\\Rightarrow s=0.315\ ft](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D4.5%5Ctimes%200.14%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-32.1%5Ctimes%200.14%5E2%5C%5C%5CRightarrow%20s%3D0.315%5C%20ft)
The highest point reached by the snowball above its release point is 0.315 ft
Total height the snowball will fall is 4+0.315 = 4.315 ft
![s=ut+\frac{1}{2}at^2\\\Rightarrow 4.315=0t+\frac{1}{2}\times 32.1\times t^2\\\Rightarrow t=\sqrt{\frac{4.315\times 2}{32.1}}\\\Rightarrow t=0.518\ s](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%204.315%3D0t%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2032.1%5Ctimes%20t%5E2%5C%5C%5CRightarrow%20t%3D%5Csqrt%7B%5Cfrac%7B4.315%5Ctimes%202%7D%7B32.1%7D%7D%5C%5C%5CRightarrow%20t%3D0.518%5C%20s)
The snowball will reach the bank at 0.14+0.518 = 0.658 seconds after it has been thrown
![v=u+at\\\Rightarrow v=0+32.1\times 0.518\\\Rightarrow v=16.62\ ft/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D0%2B32.1%5Ctimes%200.518%5C%5C%5CRightarrow%20v%3D16.62%5C%20ft%2Fs)
![v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-16.62^2}{2\times -100\times 3.28}\\\Rightarrow s=0.42\ ft](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20s%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%3D%5Cfrac%7B0%5E2-16.62%5E2%7D%7B2%5Ctimes%20-100%5Ctimes%203.28%7D%5C%5C%5CRightarrow%20s%3D0.42%5C%20ft)
The snowball goes 0.5-0.42 = 0.08 ft = 0.96 inches
Answer:
The answer to your question is:
Explanation:
There are two kinds of cell transport passive transportation and active transportation.
Passive transportation does not need energy because molecules move from higher concentration to lower concentration.
Active transportation needs energy because molecules moves against concentration.
a. facilitated diffusion It's an example of passive transportation so this answer is wrong.
b. passive transport Molecules move in favor of concentration so this answer is wrong.
c. osmosis is another example of passive transport so this answer is wrong.
d. simple diffusion it's another example of passive transport, so it's wrong this answer.
e. active transport this is the right answer.