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3 years ago

13

A motorcycle traveling south reaches a speed of 38.0 m/s. It then begins uniform negative acceleration and comes to rest after 7

.359s. How far did the motorcycle travel in this time?

1 answer:

Aleonysh [2.5K]3 years ago

6 0

Answer: 30.641

Explanation: If you get the ave which is 38.0 then the vi which is 7.359

38.0-7.359=30.641/0.0 which is 30.641

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Dmitry_Shevchenko [17]

The average speed is 20.8 m/s

Explanation:

The average speed for the trip is given by:

$v=\frac{d}{t}$

where

d is the distance covered

t is the time elapsed

For the trip in this problem, we have:

d = 187 km = 187,000 m is the distance travelled

The initial time is 10:00 pm while the arriving time is 12:30 am: this means that the time elapsed is 2.5 hours. Converting into seconds,

$t = 2.5 h \cdot (60)(60)=9000 s$

Therefore, the average speed for the trip is

$v=\frac{187,000}{9000}=20.8 m/s$

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Delicious77 [7]

The new acceleration is $108 m/s^2$

Explanation:

We can answer this problem by applying Newton's second law, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

The equation can be rewritten as

$a=\frac{F}{m}$

In this problem, the initial acceleration is

$a=18.0 m/s^2$

Later:

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Therefore, the new acceleration is:

$a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a$

which means that the new acceleration is 6 times the original acceleration, therefore

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3 years ago

suppose you needed to build a raft to cross a fast-moving river. Describe the physical and chemical properties of the raft that

erastovalidia [21]

1.Density of the material building the raft must be lower than the water.
<span>2. Material must not react with water. </span>
<span>3.Material must have high strength. </span>
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3 years ago

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen, and water. Exp

VARVARA [1.3K]

The unbalanced reaction is

<em>a</em> NH₄NO₃ ⇒ <em>b</em> N₂ + <em>c</em> O₂ + <em>d</em> H₂O

where <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em> are unknown constants.

Count how many times each element appears on either side of the reaction.

• reactants:

N = 2<em>a</em>, H = 4<em>a</em>, O = 3<em>a</em>

• products

N = 2<em>b</em>, O = 2<em>c</em> + <em>d</em>, H = 2<em>d</em>

<em />

Now we solve the system of equations,

2<em>a</em> = 2<em>b</em> … … … [1]

4<em>a</em> = 2<em>d</em> … … … [2]

3<em>a</em> = 2<em>c</em> + <em>d</em> … … … [3]

<em />

From [1] we immediately have

<em>a</em> = <em>b</em>

In [2], we get

2<em>a</em> = <em>d</em>

and substituting for <em>d</em> in [3] gives

3<em>a</em> = 2<em>c</em> + 2<em>a</em>

<em>a</em> = 2<em>c</em>

<em />

Let <em>c</em> = 1; then

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• <em>b</em> = 2

• <em>d</em> = 2×2 = 4

So, the balanced reaction is

2 NH₄NO₃ ⇒ 2 N₂ + O₂ + 4 H₂O

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3 years ago

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WITCHER [35]

Answer:

600 J

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Now, let's plug in the variables we're given and simplify.

$\frac{1}{2}(12)(10)^2$
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3 years ago

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