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mixer [17]
3 years ago
13

A motorcycle traveling south reaches a speed of 38.0 m/s. It then begins uniform negative acceleration and comes to rest after 7

.359s. How far did the motorcycle travel in this time?
Physics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Answer: 30.641

Explanation: If you get the ave which is 38.0 then the vi which is 7.359

38.0-7.359=30.641/0.0 which is 30.641

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Answer:

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Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

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We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}

B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}

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B=2.39\times 10^{-3}\ T

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 2.39\times 10^{-3}\ T. Hence, this is the required solution.

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