a²+b² = c² where a and b are legs and c is the hypotenuse
So...
a²+4²=13²
a²+16=169
a²=153
a=√153
answer: approx. 12.37 units
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Hello :
cos60 = cos(-60)=0.5
U = {points on the coordinate plane}
A = {solutions to the equation y = 2x + 5}
B = {points on the line y = mx}
Value of the slope m so that {2x + 5} ∩ {mx} =Ф
This means that {2x + 5} never intersects with {mx}
To that end m=2 (same slope), if so the 2 linear functions:
y = 2x+5 and y = 2x are PARALLEL
