Question

What is an equation of the line that passes through the points (4,1) and (8,-3)?

Answer 1

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

  so (-3-1)/(8-4)

  -4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so    1=-1(4)+b

        1=-4+b

        1+4=b

so b= 5

therefore the equation is  y=-x+5   so d