What is an equation of the line that passes through the points (4,1) and (8,-3)?

Mathematics

1 answer:

Rus_ich [418]3 years ago

8 0

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

so (-3-1)/(8-4)

-4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so 1=-1(4)+b

1=-4+b

1+4=b

so b= 5

therefore the equation is y=-x+5 so d

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