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kupik [55]
3 years ago
14

What is an equation of the line that passes through the points (4,1) and (8,-3)?

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

  so (-3-1)/(8-4)

  -4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so    1=-1(4)+b

        1=-4+b

        1+4=b

so b= 5

therefore the equation is  y=-x+5   so d

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Answer:

The LCD of the two given fraction is (x + 4)(x + 5)(x + 7)

Step-by-step explanation:

<em>In the algebraic fractions, the LCD is the least common denominator to find it do that:</em>

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<em>Let us do that with our question</em>

∵ The denominator of the first fraction is m² + 9m + 20

→ Factorize it into two factors

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<em>Do the same with the 2nd denominator</em>

∵ The denominator of the second fraction is m² + 11m + 28

→ Factorize it into two factors

∵ 28 = 4 × 7 ⇒ the last term

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∴ m² + 11m + 28 = (x + 4)(x + 7)

∴ The factors of m² + 11m + 28 are (x + 4) and (x + 7)

∵ The factors of the two denominators are (x + 4), (x + 5), (x + 4), (x + 7)

→ LCD will be all factors without repeating which means we will

   take the factor (x + 4) just one time, we will not repeat it.

∴ LCD = (x + 4)(x + 5)(x + 7)

∴ The LCD of the two given fraction is (x + 4)(x + 5)(x + 7)

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