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3 years ago

A solution that contains a small amount of salt and a large amount of water is said to be a?

1 answer:

6 0

The answer is dilute. A dilute salt solution contains a small amount of salt with high water concentration while a concentrated salt solution has a large amount of salt with a lower water concentration. Salt is inorganic hence it is not monounsaturated, which is a term related to organic compounds. The salt is unable to dissolve anymore in a saturated salt solution, leaving the undissolved salt at the bottom and this is not the case here since we only have a small amount of salt.

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The monatomic ions of Groups 1A(1) and 7A(17) are all singly charged. In what major way do they differ? Why?

insens350 [35]

Answer: Group 1 ions are known as cations and Group 17 ions are known as anions.

Explanation:

Ions are formed when an atom looses or gains electrons.

If an atom gains electrons, it leads to the formation of negative ions known as anions. For Example: Fluorine is a Group 17 element which gains 1 electron to form $F^-$ ions.

If an atom looses electrons, it leads to the formation of positive ions known as cations. For Example: Sodium is a Group 1 element which looses 1 electron to form $Na^+$ ions.

Hence, group 1 ions are known as cations and Group 17 ions are known as anions.

3 0

3 years ago

Read 2 more answers

A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu

Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0

3 years ago

How many atoms of each element are contained in a single formula unit of Iron III formate, Fe(CH02)3 x H20? What percentrage by

dedylja [7]

The percentage by mass of the compound of water is going to be 8.62%.

7 0

3 years ago

If a sample has 25% parent and 75% daughter, how many halflifes have gone by?

Anit [1.1K]

Answer:

Two half lives.

Explanation:

It is known that the decay of isotopes and radioactive material obeys first order kinetics.

Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

That means for a sample 100% to decay to 50 % it will take one half-life, and to decay the remaining 50% to 25% it will take another half-life.

So, for a sample has 25% parent and 75% daughter it will have two half-lives.

6 0

3 years ago

Consider the following reaction:

RUDIKE [14]

Answer:

H+ + Cl- + OH- + Ca2+ -> Na+ + Cl- + H2O

Explanation:

5 0

3 years ago