One of the essential minerals in the human body is salt. How much salt (NaCl) is in the average adult human body?

1 answer:

6 0

The human body contains many salts, of which sodium chloride NaCl is the major one, making up around 0.4 per cent of the body's weight. So a 50kg person would contain around 200g of sodium chloride - around 40 teaspoons. Since we lose salt whenever we sweat, it has to be continually replaced.

Answer: 0.4% of body weight.

//Not sure, but hope it helps.

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What is the best reason for the scientific community to accept a theory?

Marianna [84]

Answer: The best reason the scientific community will accept a theory is if it is proven.

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3 years ago

Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a

dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is $_2^4\textrm{He}$

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = $6.64648\times 10^{-24}g$

Mass of 1 electron = $9.10939\times 10^{-28}g$

Calculating the mass contributed by the nucleus = $m_{He}-2(m_e)$

Mass of the nucleus of He-4 atom = $6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}$

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}$

Putting values in above equation, we get:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99$

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3 years ago

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Answer: 9.18 Litres

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This question uses the Ideal Gas Equation:

PV=nRT

P= 1 atm

V = ??

T = 273 K (always convert to Kelvin unless told otherwise)

n = 0.410 mol

R = 0.0821 L.atm/mol.K

What R constant to use depends on the units of the other values. (look at the attachments) The units cancel out and only Litres is left. You simply multiply the values.