7.4x10^23 = molecules of silver nitrate sample
6.022x10^23 number of molecules per mole (Avogadro's number)
Divide molecules of AgNO3 by # of molecules per mol
7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)
(I leave off the x10^23 because they both will divide out)
Use your periodic table to find the molar weight of silver nitrate.
107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3
Now multiply your moles of AgNO3 with your molar weight of AgNO3
1.229mol x 169.868g/mol = 208.767g AgNO3
Answer:
Silver, 0.239 J/(g °C)
Explanation:
- The heat change is related to specific heat as given by the formula;
Heat change = mass of substance × specific heat × change in temperature
- Therefore; considering same amount of substance or equal masses and have the same initial temperature.
- The change in temperature will be inversely proportional to the specific heat.
- Therefore; the higher the specific heat lower the temperature change.
- Hence, the change in temperature will be highest for the substance with the lowest specific heat.
Therefore; the one that will increase in temperature the most is Silver
Chemical energy to thermal
