Answer:- The pressure of ethanol would be 109 mmHg.
Solution:- This problem is based on Clausius clapeyron equation--
Given, 
= 63.5 + 273 = 336.5 K
= 34.9 + 273 = 307.9 K
= 400 mmHg
= ?
= 39.3 kJ/mol = 39300 J/mol
R = 8.314 J/mol.K
Let's plug in the values in the equation and do the calculations.
= 1.30
On taking anti ln to both sides...
= 
= 3.67
= 400/3.67
= 109 mmHg
Answer:
166 g/mol
Explanation:
Step 1: Write the neutralization reaction
H₂A + 2 NaOH ⇒ Na₂A + 2 H₂O
Step 2: Calculate the reacting moles of NaOH
48.3 mL of 0.0700 M NaOH react.
0.0483 L × 0.0700 mol/L = 3.38 × 10⁻³ mol
Step 3: Calculate the reacting moles of H₂A
The molar ratio of H₂A to NaOH is 1:2. The reacting moles of H₂A are 1/2 × 3.38 × 10⁻³ mol = 1.69 × 10⁻³ mol.
Step 4: Calculate the molar mass of H₂A
1.69 × 10⁻³ moles of H₂A have a mass of 0.281 g. The molar mass of H₂A is:
M = 0.281 g / 1.69 × 10⁻³ mol = 166 g/mol
Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction <span> C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced</span>
