<span>9x-6y=3
</span>x -intercepts y = 0, 9x = 3 then x = 1/3
y -intercepts x = 0, -6y = 3 then y = -1/2
answer
x -intercepts (1/3, 0)
y -intercepts (0, -1/2)
Pretty sure the answer is A
Answer:
151 is your answer of this question
Step-by-step explanation:
first youvshoud divide ()and multiply by 5
Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
