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3 years ago

F(x)= -2x^3 +14x -8 g(x)= 2x+6

Mathematics

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

F(2x+6)=-16x^3-144x^3-404x-356

Step-by-step explanation:

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Order the decimals from least to greatest 3.4897, 3.3487, 1.5467, 3.348

Anna71 [15]

Answer:

1.5467, 3.348, 3.3487, 3.4897

Step-by-step explanation:

Remember to compare each one number at a time!

For the first number, only one number is 1 while the others are 3 making it the lowest.

Then when comparing 3.348 and 3.3487, it can be implied that there is a 0 at the end of 3.348 because it makes the numbers have the same # of decimal places without changing the value of the number (3.3480). That number is less than 7.

Finally, 3.4897 has a 4 in the tenths place instead of a 3 making it the highest number.

Hope this helps!

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4 years ago

The sum of a number and nine is 17. find the number

slavikrds [6]

17-9 = 8
8 is your answer.

7 0

3 years ago

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Which don’t lie??????????!!!!!

garri49 [273]

Answer:

I think its -12. If you apply y2-y1/ x2-x1 to the equation.

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4 years ago

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279÷24=? Write your answer as a whole number and remainder.

Anika [276]

Answer:

the answer is 11.625 so it is 12

Step-by-step explanation:

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3 years ago

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is 0.5 s and 7 s.

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

5 0

3 years ago