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Anna007 [38]
3 years ago
12

7t + 4 is less than or equal to 3t

Mathematics
2 answers:
Ket [755]3 years ago
6 0
-7t-3t would be -4t
4 is less than or equal to -4t
Divide 4from -4
-1 is less than or equal to t
xeze [42]3 years ago
3 0
I don't see no choices for this question but I can tell u that greater than, less than, and equal to ALL SHARE THE SAME RESULT which is -1.

Here is my work for if 7t + 4 < 3t:

4 < 3t - 7t
4 < -4t
t < -1

Even if u do greater than, less than, or equal to it would all have the same answer, it would be t < -1, t > -1, and t = -1. Either way u do it, it will still have the same answer so in terms u can say answer is both or all of the above.
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The rectangles in the figure below are similar. Find the value of x
V125BC [204]

Answer:

C. 6

Step-by-step explanation:

It is given that the rectangles in the figure are similar.

<em>Thus, the corresponding sides of the two rectangles will be equal.</em>

So, we get,

\frac{3}{x}=\frac{5}{x+4}

i.e. 3(x+4)=5x

i.e. 3x+12=5x

i.e. 2x=12

i.e. x = 6.

Hence, the value of x is 6.

3 0
3 years ago
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Which equation best represents the relationship between x and y in the graph? (PLEASE ANSWER I BEG YOU :( PLSSSSS)​
USPshnik [31]

Step-by-step explanation:

We observe the line graph.

For every 1 block across, the line goes up by 2 blocks. Therefore Slope = Rise/Run = (2)/(1) = 2.

Also, the y-intercept when x = 0 is 2.

Slope-intercept form: y = mx + c

Hence we have y = 2x + 2. (C)

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3 years ago
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The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
A laboratory has a 75-gram sample of radioactive material.
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Be more specific for yssss !!
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3 years ago
Curtis is twice as old as his brother Jonathan. Olivia is six years younger than Jonathan. The sum of their ages is 58 years.
liraira [26]
C=2 times j
c=2j
o=j-6
c+j+o=58

subsitte j-6 for o and 2j for c

2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16

sub back


c=2j
c=2(16)
c=32

o=j-6
o=16-6
o=10


curtis=32
olivia=10
jonathan=16

equations are
c+j+o=58
c=2j
o=j-6
7 0
3 years ago
Read 2 more answers
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