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BARSIC [14]
2 years ago
5

HELP FINAL!!! hello help me PLEASE I NEED THIS IM FAILING THIS IS MY FINAL

Mathematics
1 answer:
suter [353]2 years ago
4 0
Since angle IEF is angle 6 then the vertical angle should be 4
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Solve for x.<br> x^2 + 6 = 10
Ostrovityanka [42]

Steps To Solve:

x² + 6 = 10

~Subtract 6 to both sides

x² + 6 - 6 = 10 - 6

~Simplify

x² = 4

~Take square root of 4

x² = ±√4

~Simplify

x = -2 or x = 2

Best of Luck!

5 0
3 years ago
What is the period of f(x) = sin(x)? StartFraction pi Over 2 EndFraction Pi StartFraction 3 pi Over 2 EndFraction 2 pi
Nostrana [21]
<h3>Answer:  2pi</h3>

2pi radians are equal to 360 degrees. After this point, the function f(x) = sin(x) repeats its values again. Each cycle is 2pi radians long.

4 0
2 years ago
Read 2 more answers
Describe how the graph of y | x| -4 is like the graph of y= |x| and how it is different.
zhannawk [14.2K]
The graph y=|x|-4 is obtained from the graph y=|x| dy <span>moving down 4 units the graph y=|x|  along the y-axis (see, if x=0, then for y=|x|, y=0 and for y=|x|-4, y=-4).
</span>
These two graphs have the same form.
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4 0
3 years ago
Read 2 more answers
Pleaseee helpppp!!!!!!!!!!!!!!!!
SVETLANKA909090 [29]
The line g(x) has slope ...
  (change in y)/(change in x) = (-18 -(-20))/(1 - 0) = 2
so can be written in slope-intercept form as
  g(x) = 2x -20

The x-intercept of this line is at x=10.
  0 = 2x -20 . . . . the x-intercept is where g(x) = 0
  20 = 2x
  10 = x

The circle also intersects the x-axis at x=10, so that will be one point that is shared by the circle and g(x). A graph shows there is also another point of intersection, (6, -8).

Yes, the linear function g(x) will intersect the circle at 2 points with positive x-coordinates.

5 0
2 years ago
I need to show how to find these solutions 1/4 and 3/4 by completing the square!
Arlecino [84]

Answer:

See explanation, and ask for more details if unclear!

Step-by-step explanation:

The perfect square of this equation is x^2-x+\frac{1}{4}, since the square would be (x-\frac{1}{2})^2. 1/4=4/16, meaning that you can set up the equation in the following way:

(x^2-x+\frac{1}{4})-\frac{1}{16}=0

(x-\frac{1}{2})^2=\frac{1}{16}

Take the square root of both sides:

x-\frac{1}{2}=\pm \frac{1}{4}

Add 1/2 to both sides:

x=\frac{1}{2}\pm \frac{1}{4}=\frac{3}{4}, \frac{1}{4}. Hope this helps!

8 0
3 years ago
Read 2 more answers
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