Answer:
Possible C:
(1 , 1 + 3sqrt(3))
(1 , 1 - 3sqrt(3))
Step-by-step explanation:
AB = 6 units
Midpoint of AB is (1,1)
C would be at x = 1
So, (1,y)
(y-1)² + (1+2)² = 6²
(y-1)² = 36 - 9
(y-1)² = 27
y - 1 = 3sqrt(3)
y - 1 = -3sqrt(3)
y = 1 + 3sqrt(3)
y = 1 - 3sqrt(3)
Answer:
Part A: No it is not a function
Part B: The equation
Part C: x = 3
Step-by-step explanation:
Part A - The table:
Input (x) Output (y)
6 14
12 15
15 15
25 16
This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.
Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.
y = 7(6) -15
y = 42 - 15
y = 27
The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.
Part C: To find when y = 6, set it equal to 6 and solve for x.
6 = 7x - 15
21 = 7x
3 = x
Answer:
Internal validity
Step-by-step explanation:
The internal validity here is weak
Internal validity describes the extent to which an evidence weighs the cause and effect claim. In this study, the internal validity that brought about failure in the new exam is mainly due to the environment where the exam was written and not the new exam itself.
So this validity is weak in claiming that the new exam is not a good substitute for the old exam.
Putting them in the same good environment might help the researchers to draw a better conclusion.
