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3 years ago

A diver jumps from a distance that is 15 feet

Mathematics

2 answers:

WITCHER [35]3 years ago

7 0

9 ft is my answer hope this helps

V125BC [204]3 years ago

5 0

Answer:

The diver is 15 feet above surface of water so he descends 15 feet to the water. He descends another 6 feet below the water (-6). So the 15+6=21

21 feet

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

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On comparing the coefficient

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On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

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Step-by-step explanation:

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