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Pepsi [2]
3 years ago
8

Solve the following equations. log3(x^2) = 4

Mathematics
2 answers:
GenaCL600 [577]3 years ago
3 0

Answer:

x = 0.125

Step-by-step explanation:

Given:

log₃(x²) = 1

Now,

From the properties of log

logₓ (z)= \frac{\log(z)}{\log(x)}  (where the base of the log is equal for both numerator and the denominator)

also,

log(xⁿ) = n × log(x)

thus,

using the above properties, we can deduce the results as:

logₓ(y) = n is equivalent to y = xⁿ

therefore,

the given equation can be deduced as:

log₃(x²) = 1

or

2log₃(x) = 1

or

log₃(x) = 0.5

into,

x = 0.5³

or

x = 0.125

ruslelena [56]3 years ago
3 0

Answer:

x = 9

Step-by-step explanation:

given,                                        

log₃ x² = - 4              

using logarithmic identity

logₐ x = b  

x = aᵇ  

log xᵃ = a log x                                            

                   

converting into exponential form as the base is 3

log₃ x² = 4

2 log₃ x =  4

log₃ x =  2

converting

x = 3²

x = 9                        

Hence, the solution of X will be equal to x = 9            

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Step-by-step explanation:

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Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h
stepan [7]

Answer:   c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

=0.539\times100=53.9\text{ cm}   [∵ 1 m = 100 cm]             (1)

The circumference of the ash tree= 0.509 yards

=0.509\times3\text{ feet}   [∵ 1 yard = 3 feet]

=0.509\times3\times 30.48\text{ cm}  [∵ 1 foot = 30.48 cm]

=46.54296\approx46.54\text{ cm}        (2)

The circumference of the elm tree = 6281.70 millimeters

=\dfrac{6281.70}{10}=628.17\text{ cm}          (3)

The circumference of the poplar tree = 0.000385 miles

=0.000385 \times5280\text{ feet}   [∵ 1 mile = 5280 feet]

=0.000385 \times5280\times30.48\text{ feet}  [∵ 1 foot = 30.48 cm]

=61.959744\approx61.96\ \text{ cm}              (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

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5 0
3 years ago
Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans
Valentin [98]

Answer:

1.   2r+1.6b=10

2.  r=5-0.8b

3.  b=6.25-1.25r

Step-by-step explanation:

<h3> The complete exercise is: "Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans and rice for a potluck dinner. Let b be the number of pounds of beans Lin buys and r be the number of pounds of rice she buys when she spends all her money on this meal.</h3><h3>1. Write an equation relating the two variables.</h3><h3>2. Rearrange the equation so "b" is the independent variable.</h3><h3>3. Rearrange the equation so "r" is the independent variable."</h3><h3 />

1. According to the information exercise given in the exercise, the cost per pounds of brown rice is $2. Since "r" represents the number of pounds of rice Lin buys, the total cost of the brown rice she buys can be represented with this expression:

2r

The beans cost $1.60 per pound. Since "b" represents the number of pounds of beans Lin buys, the total cost of beans she buys can be represented as:

1.6b

Knowing that she spends $10, you can write the following equation:

2r+1.6b=10

2. In order to rearrange the equation so "b" is the independent variable, you need to solve for "r":

2r+1.6b=10\\\\2r=10-1.6b\\\\r=\frac{10-1.6b}{2} \\\\r=5-0.8b

3. To rearrange the equation so "r" is the independent variable, you must solve for "b". You get:

2r+1.6b=10\\\\1.6b=10-2r\\\\b=\frac{10-2r}{1.6}\\\\b=6.25-1.25r

7 0
3 years ago
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