Answer:
-37
Step-by-step explanation:
f(9)= -6X9-1
= -36-1
= -37
Answer:
Option A is correct
Values of P = -2 and Q = -31
Step-by-step explanation:
Given the equation: ![2x+Q= Px-31](https://tex.z-dn.net/?f=2x%2BQ%3D%20Px-31)
Now, we put the given values
A.
Q = -31 and P = -2
2x + (-31) = -2x - 31
2x - 31 = -2x -31
4x = -31 + 31
4x = 0
x = 0 [one solution]
B.
Q = 31 and P = 2
2x + Q = Px -31
2x + 31 = 2x -31
Subtract 2x from both sides we get
31 = -31 False.
C.
Q = -31 and P = 2
2x + (-31) = 2x - 31
2x - 31 = 2x - 31 [More than one solutions, for any x]
D.
Q = -2 and P = 2
2x + Q = Px -31
2x + (-2) = 2x -31
2x -2 = 2x -31
2x - 2x = -31 + 2
Combine like term;
0 = -29 False.
Therefore, the values of P and Q results in an equation with exactly one solution is; P = -2 and Q = -31
Answer:
$7,000
Step-by-step explanation:
Let
equal the original price.
![12,000+2000=2x](https://tex.z-dn.net/?f=12%2C000%2B2000%3D2x)
Combine like terms.
![14,000=2x](https://tex.z-dn.net/?f=14%2C000%3D2x)
Divide by the coefficient of
, which in this case is ![2.](https://tex.z-dn.net/?f=2.)
![7,000=x](https://tex.z-dn.net/?f=7%2C000%3Dx)
If you like the variable on the left, rewrite:
![x=7,000](https://tex.z-dn.net/?f=x%3D7%2C000)
A)(y2-y1)/(x2-x1)
(0-2)/(-21-3)=-2/-24=1/12
B)sqaureroot((-2)^2+(-24)^2)=squareroot(580)=2squareroot(145)
C)((x1+x2)/2,(y1+y2)/2)=(-9,1)
D)y=1/12(x+21)