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2 years ago

True or False? (–3)^22 is greater than (–2)^33

Mathematics

2 answers:

puteri [66]2 years ago

7 0

Answer:

true

Step-by-step explanation:

(-3)^22 -> to the power of an even number -> answer is positive

(-2)^33 -> to the power of an odd number -> answer is negative

positive # > negative #

Marysya12 [62]2 years ago

5 0

Answer:

True

Step-by-step explanation:

<u>First let's compare them.</u>

(-3)²²
(-2)³³

-3 raised to an even power will give a positive number.

-2 raised to an odd power will give a negative number.

Therefore, (-3)²² > (-2)³³ is a true statement.

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6. The value of (tan 1° tan2º tan 3º ... tan 89°) is

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Using the trigonometric identities

tan(90 - x) = cotx , cotx = $\frac{1}{tanx}$

Given

tan1tan2tan3....................... tan87tan88tan89

= tan1tan2tan3............... tan(90-3)tan(90-2)(tan90 - 1)

= tan1tan2tan3.............. cot3cot2cot1

= tan1cot1tan2cot2tan3cot3 ........................

= 1 × 1 × 1 ×....................... × 1

= 1

4 0

3 years ago

Find the perimeter of the triangle in inches.

madam [21]

Answer:

58 inches

<u>Step-by-step explanation:</u>

Perimeter means the sum of length of all sides of a figure.

So, the perimeter of this triangle would also be the sum of the length of its sides.

It has 3 sides.

19 in, 16 in and 23 in.

So, its perimeter equals 19 + 16+ 23

which equals 58 inches!

So, the perimeter would be 58 inches.!

3 0

2 years ago

Read 2 more answers

Integrate Sec (4x - 1) Tan (4x - 1) Dx

Delicious77 [7]

$\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill$

$\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C$

5 0

3 years ago

Will give brainliest.

lesya692 [45]

Answer:

1. y = $\frac{-A}{By}$ x + $\frac{C}{By}$

2. Divide the Opposite of A and B

3. Doesn't make sense the y-intercept is C/By sry I can't help that one

Step-by-step explanation:

1. Ax + By = C

By = -Ax + C

y = $\frac{-A}{By}$ x + $\frac{C}{By}$

2. No explanation

3 0

2 years ago

11. The probability that a dessert sold at a certain cafe contains chocolate is 75%. The probability that a dessert containing c

raketka [301]

probability that a dessert sold at a certain cafe contains chocolate is 86%.

The probability that a dessert containing chocolate also contains nuts is 30%.

Find the probability that a dessert chosen at random contains nuts given that it contains chocolate

P(nuts given chocolate) = .30/.86 = .349 or 34

6 0

3 years ago