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dimulka [17.4K]
3 years ago
7

An escaped convict runs 1.70 km due East of the prison. He then runs due North to a friend's house. If the magnitude of the conv

ict's total displacement vector is 2.50 km, what is the direction of his total displacement vector with respect to due East?
Physics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

The right approach will be "47° north of east".

Explanation:

The given values are:

East of prison

= 1.70 km

Displacement vector

= 2.50 km

Now,

The direction will be:

⇒  Cos \ \theta =\frac{1.7}{2.5}

⇒            =0.68

⇒         \theta=47.16^{\circ}

i,e.,       \theta = 47^{\circ} (north of east)

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