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2 years ago

HELP PLZ

Physics

2 answers:

Usimov [2.4K]2 years ago

7 0

The push will accelerate the box at a rate of 11.78m/s²

HOW TO CALCULATE ACCELERATION:

The acceleration of the box in this question, when pushed by a force of 777N, can be calculated as follows:

Force (N) = mass (kg) × acceleration (m/s²)

Acceleration = Force ÷ mass

Acceleration = 777 ÷ 66

Acceleration = 11.78m/s²

Therefore, the push will accelerate the box at a rate of 11.78m/s²

Learn more: brainly.com/question/24372530?referrer=searchResults

Anon25 [30]2 years ago

5 0

Answer:

A = 11.77 m/s²

Explanation:

Mass of box (m) = 66kg

Force (f) = 777n

Acceleration (a) = ??

F = ma

777 = 66 · a

A = $\frac{777}{66}$ = 11.77m/s²

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The parallel axis theorem relates Icm, the moment of inertia of an object about an axis passing through its center of mass, to I

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Answer:

Part a)

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Part b)

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Explanation:

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The position vector of a particle of mass 1.65 kg as a function of time is given by = (6.00 î + 4.15 t ĵ), where is in meters an

SashulF [63]

Answer:

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Explanation:

The definition of angular momentum is

L = r x p

Where blacks indicate vectors

Let's apply this definition our case. Linear momentum

p = m v

Let's replace

L = m r x v

The given function is

x = 6.00 i ^ + 4.15 t j ^

We look for speed

v = dx / dt

v = 0 + 4.15 j ^

To evaluate the angular momentum one of the best ways is to use determinants

$L = m \left[\begin{array}{ccc}i&j&k\\6&4.15t&0\\0&4.15&0\end{array}\right]$

L = m 6 4.15 k ^

The other products give zero

Let's calculate

L = 1.65 6 4.15 k ^

L = 41.09 Kg m2 / s

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