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2 years ago

HELP PLZ

Physics

2 answers:

Usimov [2.4K]2 years ago

7 0

The push will accelerate the box at a rate of 11.78m/s²

HOW TO CALCULATE ACCELERATION:

The acceleration of the box in this question, when pushed by a force of 777N, can be calculated as follows:

Force (N) = mass (kg) × acceleration (m/s²)

Acceleration = Force ÷ mass

Acceleration = 777 ÷ 66

Acceleration = 11.78m/s²

Therefore, the push will accelerate the box at a rate of 11.78m/s²

Learn more: brainly.com/question/24372530?referrer=searchResults

Anon25 [30]2 years ago

5 0

Answer:

A = 11.77 m/s²

Explanation:

Mass of box (m) = 66kg

Force (f) = 777n

Acceleration (a) = ??

F = ma

777 = 66 · a

A = $\frac{777}{66}$ = 11.77m/s²

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In a uniform circular motion map, what is always true? Check all that apply.

grandymaker [24]

Answer:

Velocity vectors are always perpendicular to the circle.

Acceleration vectors point toward the center of the circle.

Velocity vectors are the same length.

Explanation:

(THESE ARE NOT MY WORDS BTW)

1) Acceleration and velocity are vectorial quantities, which means they have magnitude and direction.

2) In a circular motion velocity direction changes all the time, which means that it is accelerated.

3) In a uniform circular motiion, the velocity changes in a constant value. This is the rate of change of velocity, which is the magnitude of the acceleration, is constant (uniform).

4) The velocity is perpendicular to the path, i.e. the circle. You can see it if you think that if the object stopped changing the direction, then the object would follow a straight path (as per inertia principle). That is why this velocity is called tangential velocity (to differentiate it of the angular velocity).

This is what the option C says "Velocity vectors are always perpendicular to the circle". Then this is true.

5) The constant change of direction in a circular path, means that the object is been pushed, accelerated, toward the center of a circle. This is, all the time the object in motion tries to follow the perpendicular path but a push (a force) directed to the center of the circle changes its direction. Such force accelerates the object toward the center of the circle. So, the acceleration vectors point toward the center of the circle, which is what the option D says. So, this is also true.

6) Since the motion is uniform, the magnitude or length of the velocity vectors are always the same, are constant. So, the option E. is also true.

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3 years ago

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According to this, the following shows the correct order of steps in the formation of sedimentary rocks:
C. <span>1, 4, 3, 2
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3 years ago

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A block oscillating up and down on a spring comes to the top of its path, where it is momentarily at rest. At the instant it is

True [87]

Opposite to the direction of the velocity which led it to its current position.

Explanation:

The direction of momentum when a vertically oscillating block comes to the rest momentarily will be opposite to the direction of the velocity that it has just followed to reach reach its current position.

The direction of change in momentum at the bottom will be upwards and at the top will be downwards.

The change in momentum is mathematically defined as:

$\Delta P=m.v_f-m.v_i$