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drek231 [11]
3 years ago
12

A man of 450 N covers an area of 0.0015m2 while standing on his feet.calculate the pressure exerted by him on the ground.

Chemistry
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

3×10⁵ N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 450 N

Area (A) = 0.0015 m²

Pressure (P) =?

Pressure is simply defined as the force per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

P = F/A

With the above formula, we can obtain the pressure exerted by the man on the ground. This can be obtained as follow:

Force (F) = 450 N

Area (A) = 0.0015 m²

Pressure (P) =?

P = F/A

P = 450 /0.0015

P = 3×10⁵ N/m²

Thus, the pressure exerted by the man on the ground is 3×10⁵ N/m².

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Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

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6 0
2 years ago
A gas occupies 40.0 mL at 150 K. What volume does it occupy at 300 K,
nlexa [21]

Answer:

.08 L or 80 ml

Explanation:

Use the equation V/t = V/t.

.04L / 150K = V / 300K

.04 / 150 * 300 = V

.08 L or 80 ml

6 0
3 years ago
Helpp please I would really appreciate it!!!​
KIM [24]

Answer:

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Explanation:

4 0
1 year ago
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Sunny_sXe [5.5K]

Answer:

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The newly hatched larva is in its first instar, a developmental stage that occurs between molts. It feeds until it grows too big for its cuticle, or soft shell, and then it molts. After molting, the larva is in the second instar. Ladybug larvae usually molt through four instars, or larval stages, before preparing to pupate.

Explanation:

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7 0
3 years ago
What mass of NaCl would you have dilute to 1L to make up a 0.25M solution?<br> Asap please
gavmur [86]

Answer: 0.25m

Im not sure but i think

Explanation:0.25/0.25

3 0
3 years ago
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