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aleksandrvk [35]
3 years ago
10

Am I doing this right? What is [OH-] of a solution with a pH of 4.0? Answer in M

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
4 0
Am I doing this right?

What is [OH-] of a solution
with a pH of 4.0?

Answer in M
Ya
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An ion with a charge of +3 would most likely be an element in Group ____.
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1) D
2) B
3) A
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3 years ago
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Two or more compounds that have the same molecular formula, but different arrangements of their atoms, are called_____ isomers.
dusya [7]
Structural isomers, as the structure of the molecule is different
6 0
3 years ago
Will lead (Pb) react with HgSO4?
lora16 [44]

Answer:

B

Explanation:

The electrochemical series can be used to check if a particular element has a greater activity than the other. Firstly, on the electrochemical series, it can be seen that lead is at a higher position compared to mercury. All things being equal, it will show a higher activity than mercury and hence can knock it off its salt.

Although it is the Overall standard electrode potential that tells us if a reaction is feasible or not, we can use the activity series to quickly discern if the reaction is possible or not. The overall standard electrode potential of both is positive which makes the reaction to be feasible and hence lead can display mercury off its salt

7 0
3 years ago
Calculate the ph of 0,24 m of kch3coo.? ​
Galina-37 [17]

Answer:

Correct option is A)

[H

+

]=

KaC

=

1.8×10

−6

=1.34×10

−3

pH=−log[H

+

]

=2.88

Explanation:

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6 0
3 years ago
When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.
inessss [21]

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = Energy of 1 photon = 4.30\times 10^{-19}J

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Putting values in above equation, we get:

4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0
3 years ago
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