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AysviL [449]
3 years ago
7

Ann is growing two different plants for a science project. Plant A grew 4/12 inch the first week and 2/12 inch the second week.

Plant B grew 7/12 inch the first week and didn't grow after that. Show the heights of each plant on a different number line. Which plant is taller now?
Just Show the directions on how to do the number line and give the answer ASAP please!
Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0
Start the number line from 0 and put divisions at 1/12. Then mark at 4/12 for plant A and indicate this was its growth in the first week. Then, make another mark up to 6/12 and indicate this was the plant's growth in the second week.
For plant B, make one mark at 7/12 and indicate that this is plant B's growth in the first week.

After two weeks, plant A has a height of 6/12 inches and plant B has a height of 7/12 inches, so B is taller.
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A triangle weighs 3 grams, and a circle weighs 6 grams. Use this applet to help find the weight of a square.
lesya [120]

Answer: 3.75 g

Step-by-step explanation:

Assume the weight of the square is x.

The hanger is in balance so the left side is equal to the right side.

Equation therefore is:

Triangle + Square + 3 * circle = 5* square + circle

3 + x + (3 * 6) = 5x + 6

3 + x + 18 = 5x + 6

5x - x = 3 + 18 - 6

4x = 15

x = 15/4

x =  3.75 g

7 0
3 years ago
Please dont ignore, Need help!!! Use the law of sines/cosines to find..
Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

  • \sin{A} = \sin{103\textdegree{}},
  • The opposite side of angle A a = BC = 26,
  • The angle C is to be found, and
  • The length of the side opposite to angle C c = AB = 6.

\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}.

\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}.

\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}.

Note that the inverse sine function here \sin^{-1}() is also known as arcsin.

<h3>17</h3>

By the law of cosine,

c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C},

where

  • a, b, and c are the lengths of sides of triangle ABC, and
  • \cos{C} is the cosine of angle C.

For triangle ABC:

  • b = 21,
  • c = 30,
  • The length of a (segment BC) is to be found, and
  • The cosine of angle A is \cos{123\textdegree}.

Therefore, replace C in the equation with A, and the law of cosine will become:

a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}.

\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}.

<h3>18</h3>

For triangle ABC:

  • a = 14,
  • b = 9,
  • c = 6, and
  • Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}.

\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}.

\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree.

<h3>15</h3>

For triangle DEF:

  • The length of segment DF is to be found,
  • The length of segment EF is 9,
  • The sine of angle E is \sin{64\textdegree}}, and
  • The sine of angle D is \sin{39\textdegree}.

Apply the law of sine:

\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}

\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9.

7 0
3 years ago
Jason begins at the start of a path Andy rides his bike 11 1/2 miles on the path. The path is 12 1/4 miles long. What is the dis
Damm [24]
3/4 of a mile until he reaches the end of the path.

Hope this helps.
3 0
3 years ago
Solve the equation for y. Identify the slope and y- intercept. Then graph the equation. 2y-3x=10
Shkiper50 [21]

Answer:

y=3/2x+5

The slope is 3/2 and the y-intercept is 5

Step-by-step explanation:

Solving for y will give us the slope and y-intercept

Isolate y

2y/2=10+3x/2

y=5+3/2x

The slope is 3/2 and the y-intercept is 5

Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points

7 0
3 years ago
What is the radius of the following circle?
lara [203]

Answer:

The radius is: 2\sqrt{3}

Step-by-step explanation:

The equation of a circle in center-radius form is:

(x - h)^2 + (y - k)^2 = r^2

Where the center is at the point (h, k) and the radius is "r".

So, given the equation of the circle:

x^2+y^2=12

You can identify that:

r^2=12

Then, solving for "r", you get that the radius of this circle is:

r=\sqrt{12}\\\\r=2\sqrt{3}

7 0
3 years ago
Read 2 more answers
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