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atroni [7]
2 years ago
12

From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability o

f getting 2 nickels, 2 dimes, and 1 quarter?
Mathematics
1 answer:
murzikaleks [220]2 years ago
5 0

Answer:

0.13

Step-by-step explanation:

From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once

we need to select 2 nickels from 5 nickels and select 2 dimes from 8 dimes and 1 quarter from 7 quarters

There are total of 5+8+7=20 coins

select 5 coins from total of 20 coins

2 nickels can be selected from 5 nickels in 5C2 ways

5C2=\frac{5!}{2!(5-2)!} =\frac{5!}{2!(3!)!}=10

2 dimes selected from 8 dimes

8C2=\frac{8!}{2!(8-2)!} =\frac{6!}{2!(6!)}=28

1 quarter selected from 7 quarter

7C1=\frac{7!}{1!(7-1)!} =\frac{7!}{1!(6!)}=7

5 coins selected from 20 coins

20C5=\frac{20!}{5!(15)!} =15504

probability of getting 2 nickels, 2 dimes, and 1 quarter

\frac{10 \cdot 28 \cdot 7}{15504} =\frac{1960}{15504} =0.13

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