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2 years ago

50 points and brainliest for whoever gives the best and clearest answer !

Mathematics

2 answers:

lidiya [134]2 years ago

6 0

I believe the answer is 33 3 to the fourth power subtract it from (24x2)

ser-zykov [4K]2 years ago

5 0

Answer:

i tryed

(4^{4} -2) x 1 ÷ 2+20

3^{4} - (2^{4} x 2

Equation at the end of step 1 :

(x1)

((((44)-2)•————)+(2034))-(24•x2)

Step 2 :

2.1 203 = 7•29

(203)4 = (7•29)4 = 74 • 294

Equation at the end of step 2 :

(x1)

((((44)-2)•————)+(74•294))-24x2

Step 3 :

Simplify —

Equation at the end of step 3 :

((((44) - 2) • —) + (74•294)) - 24x2

Step 4 :

4.1 4 = 22

(4)4 = (22)4 = 28

Equation at the end of step 4 :

(((28 - 2) • —) + (74•294)) - 24x2

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A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$