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2 years ago

5

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

2 answers:

solong [7]2 years ago

6 0

$Use\\\\a^2-b^2=(a-b)(a+b)\\\\i=\sqrt{-1}\to i^2=-1\\\\x^2+50=x^2-(-1)(50)=x^2-50i^2=x^2-2\cdot25i^2\\\\=x^2-2\cdot5^2i^2=x^2-2(5i)^2\\\\=x^2-(\sqrt2)^2(5i)^2=x^2-(5i\sqrt2)^2\\\\=(x-5i\sqrt2)(x+5i\sqrt2)=(x-5\sqrt2i)(x+5\sqrt2i)$

algol [13]2 years ago

3 0

$x^2+50=\\\\x^2-(-50)=\\\\
(x-\sqrt{-50})(x+\sqrt{-50})=\\\\
(x-5i\sqrt2)(x+5i\sqrt2)$

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DanielleElmas [232]

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Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

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In which

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A sample size of n is required.

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lukranit [14]

Answer:

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Step-by-step explanation:

Given:

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