Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
3 of 20
1 2 3 <u>4</u> 5 6 7 8 <u>9</u> 10 11 12 13 14 15 <u>16</u> 17 18 19 20
Answer:
The answer is "Yes, 6 = 6"
Step-by-step explanation:
If you substitute 2 for A, you would get 4 + 2 is less than or equal to 6, which is true because 6 = 6.
Hi there!
To solve this problem, we should simplify.
0.06x - 0.18 = 0.12
First, we should add 0.18 to both sides:
0.06x = 0.12 + 0.18
0.06x = 0.3
Now, we can convert 0.06 into a fraction and multiply both sides of the equation by its receprical to isolate x:
0.06 = 6/100
6/100 × 100/6 = 1
0.3 × 100/6 = 30/6
x = 30/6
x = 15/3
x = 5
So, x is 5.
Hope this helps!
The answer would be 168 minutes.